A solid cylinder of uniform density of radius 2 cm has mass of 50 g. If its length is 12 cm, calculate its moment of inertia about an axis passing through its centre and perpendicular to its length.

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#### Solution

m=50gm , L=12cm

R=2cm

`I=((ml^2)/12+(mR^2)/4)=m(l^2/12+R^2/4)`

`:.I=50[(12xx12)/12+4/4]`

= 50 x 13

=650 dyne-cm^{2}

Concept: Physical Significance of M.I (Moment of Inertia)

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